Akron elevation

Akron (Indiana, Fulton County), United States elevation is 261 meters and Akron elevation in feet is 856 ft above sea level ^{[src 1]}. Akron is a populated place (feature code) with elevation that is 18 meters (59 ft) smaller than average city elevation in United States.

Below is the Elevation map of Akron, which displays elevation range with different colors. Scale of the first map is from 239 to 286 m (784 to 938 ft) with average elevation of 259.7 meters (=852 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Akron elevation map:^{[src 2-3]}

Akron Topographic map:^{[src 2-3]}