Garrettsville elevation

Garrettsville (Ohio, Portage County), United States elevation is 304 meters and Garrettsville elevation in feet is 997 ft above sea level ^{[src 1]}. Garrettsville is a populated place (feature code) with elevation that is 25 meters (82 ft) bigger than average city elevation in United States.

Below is the Elevation map of Garrettsville, which displays elevation range with different colors. Scale of the first map is from 281 to 377 m (922 to 1237 ft) with average elevation of 325.1 meters (=1067 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Garrettsville elevation map:^{[src 2-3]}

Garrettsville Topographic map:^{[src 2-3]}