Shenandoah elevation

Shenandoah (Iowa, Page County), United States elevation is 297 meters and Shenandoah elevation in feet is 974 ft above sea level ^{[src 1]}. Shenandoah is a populated place (feature code) with elevation that is 18 meters (59 ft) bigger than average city elevation in United States.

Below is the Elevation map of Shenandoah, which displays elevation range with different colors. Scale of the first map is from 279 to 351 m (915 to 1152 ft) with average elevation of 306.5 meters (=1006 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Shenandoah elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Shenandoah Topographic map:^{[src 2-3]}