Keuka Park elevation

Keuka Park (New York, Yates County), United States elevation is 239 meters and Keuka Park elevation in feet is 784 ft above sea level ^{[src 1]}. Keuka Park is a populated place (feature code) with elevation that is 40 meters (131 ft) smaller than average city elevation in United States.

Below is the Elevation map of Keuka Park, which displays elevation range with different colors. Scale of the first map is from 218 to 439 m (715 to 1440 ft) with average elevation of 300.3 meters (=985 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Keuka Park elevation map:^{[src 2-3]}

Keuka Park Topographic map:^{[src 2-3]}