Alfred (Maine, York County), United States elevation is 83 meters and Alfred elevation in feet is 272 ft above sea level [src 1]. Alfred is a seat of a second-order administrative division (feature code) with elevation that is 196 meters (643 ft) smaller than average city elevation in United States.
Below is the Elevation map of Alfred, which displays elevation range with different colors. Scale of the first map is from 64 to 182 m (210 to 597 ft) with average elevation of 99.2 meters (=325 ft) [note 1]
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.
\ | Map #1 | Topo.Map |
Scale [m] | 64..182 m | × |
Scale [ft] | 210..597 ft | × |
Average | 99.2 m = 325 ft | × |
Width | 7.09 km = 4.4 mi | 226.9 km = 141 mi |
Height | 7.09 km = 4.4 mi | 226.9 km = 141 mi |
↑Max Latitude | 43.508351° | 44.4883° |
Latitude at center | 43.47647° | 43.47647° |
↓Min Latitude | 43.444572° | 42.4474° |
← Min Longitude | -70.762335° | -72.12464° |
Longitude center | -70.71839° | -70.71839° |
→Max Longitude | -70.674445° | -69.31214° |
Cities around Alfred sort by population:
• Sanford elevation 96 m
6.1 km, 227°
• Waterboro 82 m
6.6 km, 2°
• Lebanon 90 m
14.1 km, 229°
• Kennebunk 24 m
17.4 km, 126°
• Hollis Center 59 m
17.5 km, 35°
• South Sanford 86 m
7.5 km, 195°
• Springvale 110 m
6.2 km, 259°
• Shapleigh 178 m
12.7 km, 304°
• Acton 221 m
16.7 km, 292°
• Dayton 78 m
14.1 km, 54°
• North Berwick 43 m
19.2 km, 183°
• West Kennebunk 48 m
13.4 km, 124°
En español:
Alfred elevación 83 m.
En France:
Alfred élévation 83 m.
Sources and notes:
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