Choctaw Lake elevation

Choctaw Lake (Ohio, Madison County), United States elevation is 320 meters and Choctaw Lake elevation in feet is 1050 ft above sea level ^{[src 1]}. Choctaw Lake is a populated place (feature code) with elevation that is 41 meters (135 ft) bigger than average city elevation in United States.

Below is the Elevation map of Choctaw Lake, which displays elevation range with different colors. Scale of the first map is from 306 to 355 m (1004 to 1165 ft) with average elevation of 327.8 meters (=1075 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Choctaw Lake elevation map:^{[src 2-3]}

Choctaw Lake Topographic map:^{[src 2-3]}