Seymour elevation

Seymour (Missouri, Webster County), United States elevation is 505 meters and Seymour elevation in feet is 1657 ft above sea level ^{[src 1]}. Seymour is a populated place (feature code) with elevation that is 226 meters (741 ft) bigger than average city elevation in United States.

Below is the Elevation map of Seymour, which displays elevation range with different colors. Scale of the first map is from 449 to 516 m (1473 to 1693 ft) with average elevation of 493 meters (=1617 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Seymour elevation map:^{[src 2-3]}

Seymour Topographic map:^{[src 2-3]}