Sandy Hills elevation

Sandy Hills (Utah, Salt Lake County), United States elevation is 1459 meters and Sandy Hills elevation in feet is 4787 ft above sea level ^{[src 1]}. Sandy Hills is a section of populated place (feature code) with elevation that is 1180 meters (3871 ft) bigger than average city elevation in United States.

Below is the Elevation map of Sandy Hills, which displays elevation range with different colors. Scale of the first map is from 1338 to 1573 m (4390 to 5161 ft) with average elevation of 1426.7 meters (=4681 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Sandy Hills elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Sandy Hills Topographic map:^{[src 2-3]}