Johnstown elevation

Johnstown (Ohio, Licking County), United States elevation is 354 meters and Johnstown elevation in feet is 1161 ft above sea level ^{[src 1]}. Johnstown is a populated place (feature code) with elevation that is 75 meters (246 ft) bigger than average city elevation in United States.

Below is the Elevation map of Johnstown, which displays elevation range with different colors. Scale of the first map is from 311 to 382 m (1020 to 1253 ft) with average elevation of 343.8 meters (=1128 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Johnstown elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Johnstown Topographic map:^{[src 2-3]}