De Graff elevation

De Graff (Ohio, Logan County), United States elevation is 305 meters and De Graff elevation in feet is 1001 ft above sea level ^{[src 1]}. De Graff is a populated place (feature code) with elevation that is 26 meters (85 ft) bigger than average city elevation in United States.

Below is the Elevation map of De Graff, which displays elevation range with different colors. Scale of the first map is from 291 to 333 m (955 to 1093 ft) with average elevation of 308.8 meters (=1013 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 De Graff elevation map:^{[src 2-3]}

De Graff Topographic map:^{[src 2-3]}