Alfred elevation

Alfred (New York, Allegany County), United States elevation is 542 meters and Alfred elevation in feet is 1778 ft above sea level ^{[src 1]}. Alfred is a populated place (feature code) with elevation that is 263 meters (863 ft) bigger than average city elevation in United States.

Below is the Elevation map of Alfred, which displays elevation range with different colors. Scale of the first map is from 448 to 724 m (1470 to 2375 ft) with average elevation of 613.3 meters (=2012 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Alfred elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Alfred Topographic map:^{[src 2-3]}