Keosauqua elevation

Keosauqua (Iowa, Van Buren County), United States elevation is 179 meters and Keosauqua elevation in feet is 587 ft above sea level ^{[src 1]}. Keosauqua is a seat of a second-order administrative division (feature code) with elevation that is 100 meters (328 ft) smaller than average city elevation in United States.

Below is the Elevation map of Keosauqua, which displays elevation range with different colors. Scale of the first map is from 162 to 239 m (531 to 784 ft) with average elevation of 203 meters (=666 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Keosauqua elevation map:^{[src 2-3]}

Keosauqua Topographic map:^{[src 2-3]}