Shackle Island elevation

Shackle Island (Tennessee, Sumner County), United States elevation is 156 meters and Shackle Island elevation in feet is 512 ft above sea level ^{[src 1]}. Shackle Island is a populated place (feature code) with elevation that is 123 meters (404 ft) smaller than average city elevation in United States.

Below is the Elevation map of Shackle Island, which displays elevation range with different colors. Scale of the first map is from 140 to 264 m (459 to 866 ft) with average elevation of 189.9 meters (=623 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Shackle Island elevation map:^{[src 2-3]}

Shackle Island Topographic map:^{[src 2-3]}