Slaughterville elevation

Slaughterville (Oklahoma, Cleveland County), United States elevation is 344 meters and Slaughterville elevation in feet is 1129 ft above sea level ^{[src 1]}. Slaughterville is a populated place (feature code) with elevation that is 65 meters (213 ft) bigger than average city elevation in United States.

Below is the Elevation map of Slaughterville, which displays elevation range with different colors. Scale of the first map is from 317 to 368 m (1040 to 1207 ft) with average elevation of 340.4 meters (=1117 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Slaughterville elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Slaughterville Topographic map:^{[src 2-3]}