Petersburg elevation

Petersburg (Indiana, Pike County), United States elevation is 149 meters and Petersburg elevation in feet is 489 ft above sea level ^{[src 1]}. Petersburg is a seat of a second-order administrative division (feature code) with elevation that is 130 meters (427 ft) smaller than average city elevation in United States.

Below is the Elevation map of Petersburg, which displays elevation range with different colors. Scale of the first map is from 117 to 180 m (384 to 591 ft) with average elevation of 143.7 meters (=471 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Petersburg elevation map:^{[src 2-3]}

Petersburg Topographic map:^{[src 2-3]}