Sanford elevation

Sanford (Florida, Seminole County), United States elevation is 8 meters and Sanford elevation in feet is 26 ft above sea level ^{[src 1]}. Sanford is a seat of a second-order administrative division (feature code) with elevation that is 271 meters (889 ft) smaller than average city elevation in United States.

Below is the Elevation map of Sanford, which displays elevation range with different colors. Scale of the first map is from -8 to 32 m (-26 to 105 ft) with average elevation of 10.1 meters (=33 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Sanford elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Sanford Topographic map:^{[src 2-3]}