Jacksonville elevation

Jacksonville (Arkansas, Pulaski County), United States elevation is 90 meters and Jacksonville elevation in feet is 295 ft above sea level ^{[src 1]}. Jacksonville is a populated place (feature code) with elevation that is 189 meters (620 ft) smaller than average city elevation in United States.

Below is the Elevation map of Jacksonville, which displays elevation range with different colors. Scale of the first map is from 59 to 132 m (194 to 433 ft) with average elevation of 87.2 meters (=286 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Jacksonville elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Jacksonville Topographic map:^{[src 2-3]}