Tezu elevation

Tezu (Arunachal Pradesh, Lohit District), India elevation is 202 meters and Tezu elevation in feet is 663 ft above sea level ^{[src 1]}. Tezu is a populated place (feature code) with elevation that is 91 meters (299 ft) smaller than average city elevation in India.

Below is the Elevation map of Tezu, which displays elevation range with different colors. Scale of the first map is from 170 to 268 m (558 to 879 ft) with average elevation of 205.4 meters (=674 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Tezu elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Tezu Topographic map:^{[src 2-3]}