Searingtown elevation

Searingtown (New York, Nassau County), United States elevation is 43 meters and Searingtown elevation in feet is 141 ft above sea level ^{[src 1]}. Searingtown is a populated place (feature code) with elevation that is 236 meters (774 ft) smaller than average city elevation in United States.

Below is the Elevation map of Searingtown, which displays elevation range with different colors. Scale of the first map is from -8 to 114 m (-26 to 374 ft) with average elevation of 49.6 meters (=163 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Searingtown elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Searingtown Topographic map:^{[src 2-3]}