Secaucus elevation

Secaucus (New Jersey, Hudson County), United States elevation is 7 meters and Secaucus elevation in feet is 23 ft above sea level ^{[src 1]}. Secaucus is a populated place (feature code) with elevation that is 272 meters (892 ft) smaller than average city elevation in United States.

Below is the Elevation map of Secaucus, which displays elevation range with different colors. Scale of the first map is from -17 to 81 m (-56 to 266 ft) with average elevation of 11.7 meters (=38 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Secaucus elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Secaucus Topographic map:^{[src 2-3]}