Fargo elevation

Fargo (North Dakota, Cass County), United States elevation is 279 meters and Fargo elevation in feet is 915 ft above sea level ^{[src 1]}. Fargo is a seat of a second-order administrative division (feature code) with elevation that is 0 meters (0 ft) bigger than average city elevation in United States.

Below is the Elevation map of Fargo, which displays elevation range with different colors. Scale of the first map is from 265 to 297 m (869 to 974 ft) with average elevation of 274.9 meters (=902 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Fargo elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Fargo Topographic map:^{[src 2-3]}