Dent elevation

Dent (Ohio, Hamilton County), United States elevation is 255 meters and Dent elevation in feet is 837 ft above sea level ^{[src 1]}. Dent is a populated place (feature code) with elevation that is 24 meters (79 ft) smaller than average city elevation in United States.

Below is the Elevation map of Dent, which displays elevation range with different colors. Scale of the first map is from 150 to 289 m (492 to 948 ft) with average elevation of 242.8 meters (=797 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Dent elevation map:^{[src 2-3]}

#2 Zoom out 2x:^{[src 2-3]}

Dent Topographic map:^{[src 2-3]}