Saranpaul’ elevation

Saranpaul’ (Khanty-Mansia), Russia elevation is 32 meters and Saranpaul’ elevation in feet is 105 ft above sea level ^{[src 1]}. Saranpaul’ is a populated place (feature code) with elevation that is 167 meters (548 ft) smaller than average city elevation in Russia.

Below is the Elevation map of Saranpaul’, which displays elevation range with different colors. Scale of the first map is from 5 to 39 m (16 to 128 ft) with average elevation of 28.6 meters (=94 ft) ^{[note 1]}
These maps also provides idea of topography and contour of this city, they are displayed at different zoom levels. More info about maps, scale and edge coordinates you can find below images.

#1 Saranpaul’ elevation map:^{[src 2-3]}

Saranpaul’ Topographic map:^{[src 2-3]}